1 2 3 4 5 6 7 8 9 10 11 12 13 14
intuitionistic defaults: T --> P1; T --> P2; T --> P3; T --> P4; T --> P5; T --> P6; T --> P7; T --> P8; T --> P9; T --> P10; consequence: (P1 & P2 & P3 & P4 & P5 & P6 & P7 & P8 & P9 & P10)